Problem 25.3 Easy Free 3 variations

Call Price from Put-Call Parity

A non-dividend-paying stock trades at S0=8S_0=8. Zero-coupon bonds paying $1 at time T=1T=1 are available, with continuously compounded interest rate r=0.02r=0.02. European puts on the stock, all expiring at T=1T=1, trade at the following (strike, price) pairs: (5,0.4)(5,0.4), (10,3.2)(10,3.2), (15,5.6)(15,5.6). Using put-call parity, find the time-00 price of a European call with strike K=10K=10 and the same expiry. Give your answer to two decimal places.

Work it out, then compare with the answer.

SolutionShow the worked solution

Key idea. A long call and a short put at the same strike KK have terminal payoff

max⁡(ST−K,0)−max⁡(K−ST,0)=ST−K.\max(S_T-K,0)-\max(K-S_T,0)=S_T-K .

This is the payoff of one share minus KK zero-coupon bonds. By no arbitrage, the time-00 values agree:

C−P=S0−Ke−rT.C-P=S_0-Ke^{-rT}.

Pricing the call. Only the put with the same strike, K=10K=10, is needed; the 55 and 1515 puts play no role. With S0=8S_0=8, P=3.2P=3.2, r=0.02r=0.02 and T=1T=1:

C=P+S0−Ke−rT=3.2+8−10e−0.02.C=P+S_0-Ke^{-rT}=3.2+8-10e^{-0.02}.

Since 10e−0.02≈9.802010e^{-0.02}\approx 9.8020,

C≈11.2−9.8020=1.3980.C\approx 11.2-9.8020=1.3980 .

Check. The call is out of the money (S0<KS_0<K), so it should be cheaper than the put, which it is. It also satisfies the bound C≥max⁡(0, S0−Ke−rT)=0C\ge \max(0,\,S_0-Ke^{-rT})=0.

C=11.2−10e−0.02≈1.40\boxed{C = 11.2-10e^{-0.02}\approx 1.40}

Variations

The same idea with a twist. Each solution gives only the changed step.

Variation 25.3a

A European call struck at 120120 on a futures contract is priced at $3, and the underlying futures price is currently 110110. Assuming the discount factor between now and expiry is 11, use put-call parity for futures options (C−P=F−KC-P = F-K) to find the price of the European put struck at 120120 with the same expiry.

Work it out, then compare with the answer.

Solution

For options on a futures contract with discount factor 11, parity reads C−P=F−KC-P=F-K. Solving for the put:

P=C−(F−K)=3−(110−120)=13.P=C-(F-K)=3-(110-120)=13.

The put is in the money by 1010. On top of that intrinsic value it carries the same $3\$3 of time value as the call.

P=13\boxed{P=13}
Variation 25.3b

Stock ABC trades at $62, with interest rates and dividends both zero, and all options below expire in one month. Define a straddle as +1+1 call and +1+1 put at the same strike, and a call (put) spread as +1+1 call (put) at the higher strike minus 11 call (put) at the lower strike... actually use standard: +1+1 in-the-money option −1-1 out-of-the-money option, same type, same expiry.

The 6060-strike straddle costs $23. Using put-call parity to split the straddle into its call and put legs, find the prices of the 6060 call and the 6060 put. Then, given that the 60/6560/65 call spread (long the 6060 call, short the 6565 call) is worth $2.2, find the price of the 6565 call.

Work it out, then compare with the answer.

Solution

With zero rates and dividends, parity gives C60−P60=S0−K=62−60=2C_{60}-P_{60}=S_0-K=62-60=2. The straddle gives C60+P60=23C_{60}+P_{60}=23. Adding and subtracting these two equations:

C60=23+22=12.5,P60=23−22=10.5.C_{60}=\tfrac{23+2}{2}=12.5,\qquad P_{60}=\tfrac{23-2}{2}=10.5.

The call spread is long the 6060 call and short the 6565 call, so C60−C65=2.2C_{60}-C_{65}=2.2. Hence

C65=12.5−2.2=10.3.C_{65}=12.5-2.2=10.3.

This is consistent with call prices decreasing in strike, since C65<C60C_{65}<C_{60}.

C60=12.5,P60=10.5,C65=10.3\boxed{C_{60}=12.5,\quad P_{60}=10.5,\quad C_{65}=10.3}
Variation 25.3c

A non-dividend-paying stock trades at S0=15S_0=15. European calls expiring at the same date trade at the following (strike, price) pairs: (10,8.1)(10,8.1), (15,4.2)(15,4.2), (20,1.4)(20,1.4). Using put-call parity on each strike, find the time-00 price of the 10/15/2010/15/20 put butterfly (long one put at 1010, short two puts at 1515, long one put at 2020).

Work it out, then compare with the answer.

Solution

Let BB be the discount factor to expiry. For each strike, parity gives PK=CK−S0+KBP_K=C_K-S_0+KB. Applying this to the butterfly weights (1,−2,1)(1,-2,1):

P10−2P15+P20=(C10−2C15+C20)−(1−2+1)S0+(10−30+20)B.P_{10}-2P_{15}+P_{20}=\bigl(C_{10}-2C_{15}+C_{20}\bigr)-(1-2+1)S_0+(10-30+20)B .

Both the stock term and the bond term vanish. This is why no interest rate is needed. The remaining call combination is

C10−2C15+C20=8.1−8.4+1.4=1.1.C_{10}-2C_{15}+C_{20}=8.1-8.4+1.4=1.1 .

So the put butterfly costs the same as the call butterfly, as it must, since their payoffs are identical.

1.1\boxed{1.1}